Path: utzoo!utgpu!jarvis.csri.toronto.edu!rutgers!apple!usc!cs.utexas.edu!uunet!yale!cmcl2!lanl!jlg
From: jlg@lanl.gov (Jim Giles)
Newsgroups: comp.lang.c
Subject: Re: int divided by unsigned.
Message-ID: <13981@lanl.gov>
Date: 11 Jul 89 06:12:08 GMT
References: <1578@mcgill-vision.UUCP>
Distribution: na
Organization: Los Alamos National Laboratory
Lines: 10

From article <1578@mcgill-vision.UUCP>, by mouse@mcgill-vision.UUCP (der Mouse):
> [...]
> Really?  As in 65500U / 6 giving -6 (sixteen bit ints)?[%]  Take your
> pick, you get either that -100 / 10U giving 654.  [...]

If you've really been following this discussion, you will remember that
my _favorite_ fix for the mixed mode problem is to promote _both_ operands
to long.  This would give 65500/6 == 10916 _AND_ it would give -5/1000u == 0.
Of course, as someone also pointed out, C foolishly doesn't require 'short',
'int', and 'long' to be different data types.  Oh well.