Path: utzoo!utgpu!jarvis.csri.toronto.edu!mailrus!ames!apple!rutgers!dptg!ulysses!andante!alice!debra
From: debra@alice.UUCP (Paul De Bra)
Newsgroups: comp.lang.c
Subject: Re: comma operator
Message-ID: <9736@alice.UUCP>
Date: 4 Aug 89 13:25:07 GMT
References: <10099@mpx2.mpx.com> <93@microsoft.UUCP> <10100@mpx2.mpx.com> <918@helios.toronto.edu> <13074@megaron.arizona.edu>
Reply-To: debra@alice.UUCP ()
Organization: AT&T, Bell Labs
Lines: 36

In article <13074@megaron.arizona.edu> robert@arizona.edu (Robert J. Drabek) writes:
}...
}I agree with you.  The one place, though, where it is used is in "for"
}loops:  for (i = 0, j = 9; ...; i++, j--)
}
}I have seen the following "attempt" at using a comma operator in a function
}call:
}
}       func(expr1, expr2)
}
}The writer thought he was using the comma operator since the function
}had been defined as having a single argument.  He did get
>
}       func((expr1, expr2))
}
}to work.  I don't know if all compilers would get this, though.

The following is also a problem:
if i have something like
	if (e)
		return;
and want to get some debug output, i would try
	if (e)
		printf("Hi\n"),return;
but this gives syntax error. (at least in the compilers i've tried)
Note that
	if (e)
		printf("Hi\n"),exit();
compiles fine. It's just that "return" is treated differently.

Paul

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