Xref: utzoo comp.sys.ibm.pc:32269 comp.binaries.ibm.pc.d:3976 Path: utzoo!attcan!utgpu!watmath!julian!uwovax!2014_5001 From: 2014_5001@uwovax.uwo.ca Newsgroups: comp.sys.ibm.pc,comp.binaries.ibm.pc.d Subject: Help with strange partitioning--logical drive setup Message-ID: <3216@uwovax.uwo.ca> Date: 28 Jul 89 14:11:07 GMT Lines: 35 I have my hard drive partitioned into a DOS3.3 partition and a DOS2.11 partition (Why? Simply as DOS2.11 gives me more free RAM, which I do need). I would like to be able to access the DOS2.11 partition from within the DOS3.3 partition, so I need not use floppies to xfer data. Unfortunately, the DOS3.3 logical drive configuration is done by fdisk, which means that with it I can only assign logical names to DOS3.3 drives. I tried fooling it by first creating an extended DOS3.3 partition, and then tweaking the partition table by hand (Adv NU 4.0), but the logical drive assignments were lost. Query 1. Is there a PD program that will assign logical drives to partitions? Query 2. If not, is there some way I can xfer data between the two partitions, without using floppies? Perhaps keeping a ramdisk open between boots on the two partitions? Query 3. Has anyone ever partitioned a disk into different DOS versions before? Did he/she have any other problems with such a partitioning? Query 4. Is there perhaps another way of getting more RAM, other than switching to DOS2.11? I cannot afford any ex[pt]ended RAM, and my programs still would not be able to use it. I really do need about 20Kb more RAM. Not more. 20 is enough, that's why it is sufficient to switch to DOS2.11. -- !---------------------------------------------------------------------------! ! Alexander Pruss, at one of: Department of Applied Mathematics, Astronomy, ! ! Mathematics, or Physics University of Western Ontario ! ! pruss@uwovax.uwo.ca pruss@uwovax.BITNET A5001@nve.uwo.ca ! ! If I don't respond: try mayhem@uwovax.BITNET or mayhem@uwovax.uwo.ca ! !-----------Question.TeX----------------------------------------------------! ! "Is it ${\bf G}=8\pi{\bf T},$ or is it ! ! $i\hbar {{d\left| Pt\right>}\over {t dt}}={\cal H}\left| Pt \right>.$? ! ! ... Or both approximately???" -- Anonymous ! !---------------------------------------------------------------------------!