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From: zweig@brutus.cs.uiuc.edu (Johnny Zweig)
Newsgroups: comp.lang.c++
Subject: Re: 'this' question
Message-ID: <1989Sep12.010035.3886@brutus.cs.uiuc.edu>
Date: 12 Sep 89 01:00:35 GMT
References: <14232@polyslo.CalPoly.EDU> <6590244@hplsla.HP.COM>
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>//> Wang:
>//> When I write:
>//> 
>//> type_student* me = new type_student();
>//> 
>//> Is the address of 'me' guaranteed to be the same as the value of 'this'
>//> for the 'me' object?

Guaranteed not to be. &me would be the address of the pointer me. The
VALUE stored in me has to be the same as the address of the type_student
object, for example:

type_student::f( type_student * p ) {
	printf("%x %x\n", this, p );
}

will print the same number twice if you were to call me->f( me );. "this"
is defined as a pointer to the object -- I imagine it would break a lot
of code if somehow a pointer to object X and X.this couldn't be compared
with == sensibly.

-Johnny this