Path: utzoo!utgpu!jarvis.csri.toronto.edu!mailrus!uwm.edu!uakari.primate.wisc.edu!aplcen!haven!adm!smoke!gwyn From: gwyn@smoke.BRL.MIL (Doug Gwyn) Newsgroups: comp.lang.c Subject: Re: type *var -- vs. -- type* var Message-ID: <11033@smoke.BRL.MIL> Date: 12 Sep 89 03:21:50 GMT References: <4201@ohstpy.mps.ohio-state.edu> <29048@news.Think.COM> <12813@pur-ee.UUCP> <10992@smoke.BRL.MIL> <1014@m3.mfci.UUCP> Reply-To: gwyn@brl.arpa (Doug Gwyn) Organization: Ballistic Research Lab (BRL), APG, MD. Lines: 13 In article <1014@m3.mfci.UUCP> karzes@mfci.UUCP (Tom Karzes) writes: -In article <10992@smoke.BRL.MIL> gwyn@brl.arpa (Doug Gwyn) writes: ->In article <12813@pur-ee.UUCP> lewie@ecn-ee.UUCP writes: ->>Because there's no explicit separator between declarations and statements, ->>you'll never be able to declare pointers as such. Isn't C syntax fun? ->Anyone who programs in C frequently declares pointers as such. -This statement is a nonsequitur. C programmers do frequently declare -pointers to ints, but they certainly don't use the above syntax to do -so, which is what you unwittingly claimed. I got a note from lewie; it turns out that the misunderstanding lies in the usage of the phrase "as such". He meant in the cast-like format. I would have said "like that" instead of "as such"..