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From: jik@athena.mit.edu (Jonathan I. Kamens)
Newsgroups: comp.unix.wizards
Subject: Re: ls -A
Message-ID: <15015@bloom-beacon.MIT.EDU>
Date: 11 Oct 89 01:59:46 GMT
References: <15@minya.UUCP> <14611@bloom-beacon.MIT.EDU> <1989Oct6.201107.9465@eci386.uucp> <1989Oct7.032907.27496@rpi.edu> <MRD.89Oct7205748@sun.clarkson.edu> <1989Oct8.212100.12355@rpi.edu> <6468@ficc.uu.net> <602@buster.irby.com>
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Reply-To: jik@athena.mit.edu (Jonathan I. Kamens)
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In article <602@buster.irby.com> rli@buster.irby.com (Buster Irby) writes:
=peter@ficc.uu.net (Peter da Silva) writes:
=
==grep 'pattern' .??* *
=
=Sorry Peter, but you just flunked your Unix Wizards Test!  The
='.??*' you mentioned above will not only exclude '.' and '..'
=from the glob, but will exclude all '.?' files such as ".a", ".B", 
=from the glob as well.  If you are using the Bourne or the Korn shell, 
=you can try this instead:
=
=grep 'pattern' .[!.]* ..?* *
=
=The middle pattern '..?*' is only needed if you are in the habit of
=creating hidden files with two or more leading dots instead of 
=just one, such as '..a' or '..B', otherwise it can be excluded.

  Actually, ".??* *" is sufficient unless you are "in the habit of
creating hidden files" matching the ".?" pattern.

  :-)

Jonathan Kamens			              USnail:
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