Path: utzoo!attcan!uunet!ginosko!usc!rutgers!mit-eddie!uw-beaver!ubc-cs!alberta!oha!tony
From: tony@oha.UUCP (Tony Olekshy)
Newsgroups: comp.lang.c
Subject: Re: on the fringe of C syntax/semantics
Summary: cdecl *does* allow declaration of argument types!
Message-ID: <334@oha.UUCP>
Date: 14 Oct 89 20:07:08 GMT
References: <789@crdos1.crd.ge.COM> <457@usage.csd.unsw.oz> <20077@mimsy.UUCP>
Reply-To: tony@oha.UUCP
Organization: Olekshy Hoover & Associates Ltd., Edmonton, Alberta, Canada.
Lines: 33
In-Reply-To: Message <20077@mimsy.UUCP> dated 9 Oct 89 18:59:09 GMT
Return-Path: <alberta!oha!tony>

In message <20077@mimsy.UUCP>, chris@mimsy.UUCP (Chris Torek) writes:
>
> One can use the freely-available (possibly public domain) `cdecl'
> program to come up with things like [...]
>
> 	char **(*(**(*(*(*(*(*foo)())())[3])())[4][2])())[5]
> 
> Of course, in ANSI C, one should include the types of the arguments to
> each of the functions....

FYI:

    (echo `cat` | cdecl) << \_end_
    declare foo as pointer to function (a,b) returning pointer to
    function (c, d) returning pointer to array 3 of pointer to
    function (e, f) returning pointer to array 4 of array 2 of
    pointer to pointer to function (g, h) returning pointer to
    array 5 of pointer to pointer to char
    _end_

Generates:

    char **(*(**(*(*(*(*(*foo)(a, b))(c, d))[3])(e, f))[4][2])(g, h))[5]

So, isn't:

    typedef int a, b, c, d, e, f;
    (char **(*(**(*(*(*(*(*)(a, b))(c, d))[3])(e, f))[4][2])(g, h))[5])x;

ok?

--
Yours, etc., Tony Olekshy (...!alberta!oha!tony or tony@oha.UUCP).