Xref: utzoo sci.space.shuttle:3905 sci.space:14979 Path: utzoo!attcan!utgpu!jarvis.csri.toronto.edu!mailrus!cs.utexas.edu!uunet!crdgw1!crdos1!davidsen From: davidsen@crdos1.crd.ge.COM (Wm E Davidsen Jr) Newsgroups: sci.space.shuttle,sci.space Subject: Re: Exhaust velocity Message-ID: <1437@crdos1.crd.ge.COM> Date: 24 Oct 89 21:45:35 GMT References: <538.252A3A3B@mamab.FIDONET.ORG> <34577@srcsip.UUCP> <1989Oct23.203306.24154@brutus.cs.uiuc.edu> Reply-To: davidsen@crdos1.UUCP (bill davidsen) Followup-To: sci.space.shuttle Organization: GE Corp R&D Center Lines: 41 In article <1989Oct23.203306.24154@brutus.cs.uiuc.edu>, zweig@brutus.cs.uiuc.edu (Johnny Zweig) writes: | I can't quite hack all the Isp, TC/m, and other mumbo-jumbo. I think it boils | down to the fact that the mass-flow (Kg/S) out the back of the motor gives | you part of your thrust, and the interaction between what comes out the back | "pressing against" the atmosphere is another. So if I have two rockets that | spit out the same mass of stuff per second, but one has higher nozzle | pressure, that one will give me somewhat more thrust off the launchpad (once | up in space there should be no difference since there's no atmosphere). Let me try to explain how this works. Picture a sphere filled with a pressurized fluid. Call it a ballon full of hot air. If you bisect the sphere with a plane (like, cut it in half), the pressure against each half will be equal. No thrust. Now open a hole in the sphere and let pressure escape (let go of the next of the balloon). If you think about the sphere pressure now, the inner pressure is P (say 10 psi), and the diameter of the nozzle is D (say 1/4 inch). That's an area of .785 square inches, which would have had a pressure of 7.85 pounds against it. Therefore the "front" of the balloon (or combustion chamber) has 7.85 lb more pressure on it than the back. There are also action/reaction effects which are independent of the pressure. Note that atmospheric pressure didn't come into any of this, except that it raises the pressure in the combustion chamber by a tiny amount and therefore raises the thrust. Since lack of atmosphere will effect either of the rockets you mentioned, there will still be more thrust for the higher pressure. Since you said the samme mass per unit time, the *velocity* may well be higher, as well, depending on the density of the exhaust. Correct or expand on this as appropriate. The guy said he wasn't a physicist so I didn't use metric. -- bill davidsen (davidsen@crdos1.crd.GE.COM -or- uunet!crdgw1!crdos1!davidsen) "The world is filled with fools. They blindly follow their so-called 'reason' in the face of the church and common sense. Any fool can see that the world is flat!" - anon