Path: utzoo!utgpu!jarvis.csri.toronto.edu!mailrus!wuarchive!texbell!sequoia!rpp386!woody
From: woody@rpp386.cactus.org (Woodrow Baker)
Newsgroups: comp.unix.wizards
Subject: Re: pronunciation of *
Summary: pronouncing *
Message-ID: <17292@rpp386.cactus.org>
Date: 13 Nov 89 13:50:20 GMT
References: <5047@yarra.oz.au> <9945@attctc.Dallas.TX.US> <1234@unify.UUCP>
Organization: River Parishes Programming, Plano, TX
Lines: 18

In article <1234@unify.UUCP>, dgh@unify.UUCP (David Harrington) writes:
> In article <303@orchid.warwick.ac.uk> maujt@warwick.ac.uk (Richard J Cox) writes:
> >In article <469020f0.81da@digital.sps.mot.com> chen@digital.sps.MOT.COM (Jinfu Chen) writes:
> >>In article <9945@attctc.Dallas.TX.US> nasa@attctc.Dallas.TX.US (Daniel Poirot) writes:
> >>>
> >>>How do you pronounce '*'?  
> >>>
> >>
When I first got started with 'C' I had a &^$%^* (ha) of a time understanding
pointers.  It only became clear when my guru (all beginning 'C'ers need a guru)
told me to pronounce it as    'at'   It would have made a lot more sense
for K & R to have defined    '@' to be the indirection operator, since it is
not used, and since it unloads the '*' a bit, but it was not done.

char * pointer   ====>verbalizes as    char at pointer    which clearly
states the concept.

cheers, Woody