Path: utzoo!utgpu!jarvis.csri.toronto.edu!mailrus!cs.utexas.edu!wuarchive!brutus.cs.uiuc.edu!apple!mips!prls!pyramid!leadsv!practic!vlsisj!davidc From: davidc@vlsisj.VLSI.COM (David Chapman) Newsgroups: sci.electronics Subject: Re: Ease up on the current Summary: larger resistance Message-ID: <15385@vlsisj.VLSI.COM> Date: 10 Nov 89 01:05:47 GMT References: <763@tardis.Tymnet.COM> Reply-To: davidc@vlsisj.UUCP (David Chapman) Distribution: na Organization: VLSI Technology Inc., San Jose, CA Lines: 33 In article <763@tardis.Tymnet.COM> jenglish@tardis.Tymnet.COM (Jim English) writes: >I know this is probably elementary knowledge, but I'll ask >anyway. What would I need to do to a simple circuit to lighten >the current on it. Basically, the power (DC) comes in, passes >through a resistor, a transistor, and drives a light display. >The resistor and transistor get quite hot. I am using a 5 watt >resistor, and it hasn't helped. Do I put a cap across the >resistor? The normal way to reduce the current is to use a larger resistor (in ohms, not in watts). Unfortunately, this also reduces the voltage to the display. Hmmmm, maybe not. If the transistor is doing any voltage regulation then it might not be so bad. Try a somewhat higher resistor (increase in 5-10% steps) and see what happens. Stick with the 5W size, though. The wattage is the amount of energy the part can dissipate without failing. It doesn't _necessarily_ mean it would be cooler if it had a higher wattage (but you don't really want to know about thermal conductance :-). The transistor definitely should NOT be hot, though. You might want to compute the current through it to make sure you're not exceeding its limits. The easiest way is probably to measure the voltage across the resistor. If you're still having problems, post the input voltage, the resistance, and the output voltage required (to the display) and we'll take a look at it. -- David Chapman {known world}!decwrl!vlsisj!fndry!davidc vlsisj!fndry!davidc@decwrl.dec.com