Path: utzoo!utgpu!jarvis.csri.toronto.edu!mailrus!accuvax.nwu.edu!nucsrl!telecom-request From: John Higdon Newsgroups: comp.dcom.telecom Subject: Re: Two Lines From a Twisted Three? Message-ID: <1756@accuvax.nwu.edu> Date: 2 Dec 89 21:21:29 GMT Sender: news@accuvax.nwu.edu Organization: Green Hills and Cows Lines: 28 Approved: Telecom@eecs.nwu.edu X-Submissions-To: telecom@eecs.nwu.edu X-Administrivia-To: telecom-request@eecs.nwu.edu X-Telecom-Digest: Volume 9, Issue 546, message 4 of 4 In article , owens%tartarus@ gargoyle.uchicago.edu (Christopher Owens) writes: > I've been told there is a way to use some kind of bridge circuit at > each end of a 3-conductor wire to enable two phone lines to be run > over the wire. Does anyone know about this. If they exist, where can > one get them? This didn't sound like any kind of fancy multiplexing, > just a bridged circuit of some kind. Would it leave me with a clean > line and full bandwidth? How would it interact with a high-speed > modem on one of the lines? My earlier rantings on the subject notwithstanding, probably the most practical and reliable way to get your second service would be to use a subscriber carrier device. There is a way to phantom a third service from two pairs, but that doesn't apply here. Whatever you do, NEVER pick conductors from two different cables to serve as your "pair". This, in effect, causes your line to look like an unbalance circuit in each of the cables you have selected and there will be major crosstalk. In other words, don't take the third conductor from, say your existing service and your neighbor's service, to supply the run for your second line. Everyone will end up talking to everyone else. John Higdon | P. O. Box 7648 | +1 408 723 1395 john@zygot.ati.com | San Jose, CA 95150 | M o o !