Path: utzoo!utgpu!watserv1!watmath!iuvax!mailrus!tut.cis.ohio-state.edu!oz.cis.ohio-state.edu!jgreely
From: jgreely@oz.cis.ohio-state.edu (J Greely)
Newsgroups: comp.unix.questions
Subject: Re: Simple question...
Message-ID: <JGREELY.89Dec2101808@oz.cis.ohio-state.edu>
Date: 2 Dec 89 15:18:08 GMT
References: <3013@uceng.UC.EDU>
Sender: news@tut.cis.ohio-state.edu
Reply-To: J Greely <jgreely@cis.ohio-state.edu>
Organization: Ohio State University Computer and Information Science
Lines: 26
In-reply-to: schriste@uceng.UC.EDU's message of 2 Dec 89 13:18:01 GMT

In article <3013@uceng.UC.EDU> schriste@uceng.UC.EDU
 (Steven V. Christensen) writes:
>Excuse the simple question, but I have a bunch of shar files that
>I want to unshar. Unfortunately all 20+ have the mail headers on them.
>In SED, how would I pipe the files to remove everything before the
>"#!/bin/sh" ?

Strictly speaking, you need to remove everthing before the first line
that begins with either "#" or ":", since many shar programs produce
the latter.

	sed -n '/^[#:]/,$ p'

is the command you're looking for.

> Also, how would I get everything between the "#!/bin/sh"
>and the "exit 0" at the end (for those mailers which append a .sig)?

You don't.  The "exit 0" is there specifically to prevent the shell
from reading the signature.


Of course, to beat a dead horse, you can do it in perl like this:
	perl -ne 'print if /^[#:]/..eof();'
-=-
J Greely (jgreely@cis.ohio-state.edu; osu-cis!jgreely)