Path: utzoo!attcan!uunet!cs.utexas.edu!news-server.csri.toronto.edu!utgpu!watserv1!mgardi
From: mgardi@watserv1.waterloo.edu (Mutual Life)
Newsgroups: comp.lang.c++
Subject: Re: The type yielded by "new T[expression]"
Message-ID: <1550@watserv1.waterloo.edu>
Date: 21 Mar 90 17:55:04 GMT
References: <26068361.27247@paris.ics.uci.edu>
Organization: University of Waterloo
Lines: 47

In article <26068361.27247@paris.ics.uci.edu> rfg@paris.ics.uci.edu (Ronald Guilmette) writes:
>One minor footnote.  It was formerly the case that any attempts to "delete"
>arrays of objects had to include a square-bracketed size expression in
>the delete statement, i.e.:
>
>	delete [size] ptr;
>
>It appears that this has changed recently, and that the proper way to do
>this now is simply:
>
>	delete [] ptr;
>
I came across some interesting code in the C++ work conference proceedings.
here goes:

str = new char[length + 1];

...
delete [length + 1] str;

I assume this is not necessary (is it correct?) for built in types....

Also, in the string class mentioned in the 'first course in c++', they
do the following:

String&
String::operator=(const String& right)
	{
	if (this == &right)
		return *this;

well...my compiler (zortech) complains about this (appropriately I 
think?) and I have to use a temporary 'const String temp'
to do the comparison to 'right'. Is this the way it should be? Why the
problem...I am taking an address of a const, but not for assignment...
p.

Peter DeVries
Mutual Life of Canada
c/o mgardi@watdcsu
(519) 888-3523
(416) 972-0594

My opinions/comments are mine, and mine only, and have nothing
to do with what Mutual Life of Canada thinks (now isn't that
an understatement!)
p.