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From: brad@SSD.CSD.HARRIS.COM (Brad Appleton)
Newsgroups: comp.unix.questions
Subject: Re: Bourne Shell (/bin/sh) counting?
Summary: What exactly was the question asker trying to do anyway
Keywords: shell
Message-ID: <3350@hcx1.SSD.CSD.HARRIS.COM>
Date: 20 Mar 90 15:14:49 GMT
References: <22788@adm.BRL.MIL> <63524@srcsip.UUCP>
Sender: news@hcx1.SSD.CSD.HARRIS.COM
Organization: Harris Computer Systems, Fort Lauderdale, FL
Lines: 44

In article <22788@adm.BRL.MIL> rbottin@atl.calstate.edu (Richard John Botting) writes:
>Jeff <postnews@cvbnetprime.com> Asks
>>  What is the best way to provide a loop counter in a Bourne
>>  shell script? An example script is below, all it needs is
>>  the count incrementer.
>
>>      #!/bin/sh
>>      count=0
>[...]
>>        # <increment count here>
>>       echo count=$count
> ...
>
> [ points out significant details in using 'expr' ]
> ...
>I'd like to see a neat solution (other than a "increment.c" program).


This is the easiest one yet (using the original example):

        #!/bin/sh
        count=0
	for i in 1 2 3 4 5 6 7 ; do
            count=$i
        done

Has the same effect as incrementing count (and is "plainer" too).
Or better yet:

        #!/bin/sh
        count=7

I guess what Im really asking is:

Why did the asker of the original question need to do the 
incrementing if the for loop was already incrementing a variable 
for him? I think if we knew this we could all provide some assistance 
in helping him find the "nicest" way to do it.

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|  Brad Appleton                       |  Harris Corporation         |
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