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From: brad@SSD.CSD.HARRIS.COM (Brad Appleton)
Newsgroups: comp.unix.questions
Subject: Re: Bourne Shell (/bin/sh) counting?
Summary: use expr
Keywords: expr, Bourne Shell
Message-ID: <3329@hcx1.SSD.CSD.HARRIS.COM>
Date: 19 Mar 90 16:02:25 GMT
References: <124@cvbnetPrime.COM>
Sender: news@hcx1.SSD.CSD.HARRIS.COM
Distribution: usa
Organization: Harris Computer Systems, Fort Lauderdale, FL
Lines: 46

In article <124@cvbnetPrime.COM> jsulliva@cvbnet.UUCP (Jeff Sullivan, x4096 MS 4-2) writes:
>
>  What is the best way to provide a loop counter in a Bourne
>  shell script? An example script is below, all it needs is
>  the count incrementer.
>
>      #!/bin/sh
>      count=0
>
>      for i in 1 2 3 4 5 6 7 8 9
>      do
>	# <increment count here>
>	echo count=$count
>      done
>
>  I know there are other ways to accomplish the same thing,
>  (such as the Korn shell), but I'd really like to know how
>  to accomplish the above.
>

First off, I apologize for leaving out the summary in my last post.

Now ...
In the Bourne shell, you can do "arithmetic" with expr. Expr can do 
lots of other stuff too (like pattern matching, and returning portions 
of strings ... read up on it! it is *very* useful).

 Anyway, here is an example:

     $ count=1
     $ count=`expr $count + 1`
     $ echo $count
     2
     $

Hope this helps!

PS - you may want to use a while loop instead of a for loop for your 
     loop counting. Then again, in my experience, "while" is slower.

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