Path: utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!swrinde!zaphod.mps.ohio-state.edu!uwm.edu!ux1.cso.uiuc.edu!ux1.cso.uiuc.edu!uicsgva.csg.uiuc.edu!patel From: patel@uicsgva.csg.uiuc.edu Newsgroups: comp.arch Subject: Re: Questions about DRAM's Message-ID: <1600020@uicsgva.csg.uiuc.edu> Date: 10 Apr 90 00:29:16 GMT References: <28686@cup.portal.com> Lines: 45 Nf-ID: #R:cup.portal.com:28686:uicsgva.csg.uiuc.edu:1600020:000:1942 Nf-From: uicsgva.csg.uiuc.edu!patel Apr 9 16:07:00 1990 I am not a VLSI or Memory Expert but some of this information you can find in literature on memory. Most likely, this note is not being read by RAM designers, so I thought I should clear up the picture on RAM. DRAMs: Present day DRAMs use a 3-D capacitor, called Trench Capacitor. A Trench Capacitor has a small footprint on chip but effectively gives you a larger surface area. By contrast a 2-D (planar) capacitor has an effective area equal to its footprint. From Physics/EE 101 everyone should recall that the capacitance is proposrtional to the area of the parallel plates. 2-D Capacitor Trench Capacitor ---~~~~~--- --- --- ---~~~~~--- --\\ //-- \\_// \_/ So the trecnch capacitor has a capacitance larger than an equal-footprint planar capacitor. You need a large capacitor 1. To hold the data for reasonable time before you need a refresh. Charge retention depends heavily on your process, how good is your manufacturing process to hold the leakage currents to a minimum etc. 2. To tell the difference between charge (1) and no-charge(0)! In fact this is a very serious problem. Unlike ordinary logic levels, (0 for < 1 volt and 1 for > 2.5 volts) you have to sense very small voltage swings between a logic 0 and 1. To sense the presence of an extremely small charge against various odds (noise, leakage, long wires, temperature variations etc.) is no small feat. Design of sense amps is considered a black art. SRAMs: Static RAM cell does not need a capacitor to work. Static RAMs canont be scaled down arbitrarily for the same reason as DRAM can't. The same problem exists with small transitors as with small capacitors, namely, driving long lines and reliably differentiating between 1 and 0 at the sense amp. -J. Patel Univ. of Illinois, Urbana-Champaign patel@csg.uiuc.edu