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From: horstman@sjsumcs.sjsu.edu (Cay Horstmann)
Newsgroups: comp.lang.c++
Subject: Re: PolyMorphism
Message-ID: <1990Apr11.053453.11504@sjsumcs.sjsu.edu>
Date: 11 Apr 90 05:34:53 GMT
References: <CHIN.90Apr9174555@sg1.chem.upenn.edu>
Reply-To: horstman@sjsumcs.SJSU.EDU (Cay Horstmann)
Distribution: comp
Organization: San Jose State University
Lines: 33

In article <CHIN.90Apr9174555@sg1.chem.upenn.edu> chin@sg1.chem.upenn.edu (Chin Wu) writes:
>
>    If we use a Base pointer to construct a Derived object, will the
>Derived destructer be used when been deleted? I have used the
>following code to explore:
>
>class Base
>{
>  public:
>    Base() { cout << "This is base constructer\n";};
>    ~Base() { cout << "This is base destructer\n";};
>};
>
>class Derived : public Base
>{
>  public:
>    Derived() { cout << "This is derived constructer\n";};
>    ~Derived() { cout << "This is derived destructer\n";};
>};
>
>main()
>{
>    Base* test;
>
>    test = new Derived;
>    delete test;
>}    
>... is there anyway you can call Derived class
>destructer?
>
Yes. Declare the destructor to be virtual (in the Base.)

Cay