Path: utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!usc!apple!bionet!ames!ncar!mephisto!prism!gt4589b From: gt4589b@prism.gatech.EDU (Davis, Jr., Martin H.) Newsgroups: comp.sys.zenith.z100 Subject: Checking for 8087 Keywords: monitor,8087 Message-ID: <7872@hydra.gatech.EDU> Date: 11 Apr 90 01:39:14 GMT Organization: Georgia Institute of Technology Lines: 24 I recently bought (used) the Easy87 8087 coprocessor board. In the in- structions, they said I should put the system in the monitor mode, and at the "familiar" hand prompt, depress the "S" key. The instructions said if I had installed the 8087 properly, then "8087" would appear in response to the "S" command at the hand prompt. However, "8087" does not appear. However, I know for a fact the Z-100 is making use of the 8087 ith appropriate software). I use the Microsoft QuickC 2.0 for development simulation work, and when it is compiled in a default manner, it tests for the 8087 and uses it if present. Thus programs that previously took 100 secs. run in 5 secs, so I know that QuickC 2.0 finds the 8087. I guess my question is: Are the Easy87 instructions wrong in saying the "8087" should appear in response to the "S" command? Or, is there some- thing (like a jumper, whatever, etc.) I should have set when I installed the coprocessor? I guess I'm just curious more than anything else since the only application I have that can use the 8087 is the QuickC. -- DAVIS,MARTIN HENRY JR Georgia Institute of Technology, Atlanta Georgia, 30332 uucp: ...!{allegra,amd,hplabs,seismo,ut-ngp}!gatech!prism!gt4589b ARPA: gt4589b@prism.gatech.edu