Path: utzoo!censor!geac!torsqnt!news-server.csri.toronto.edu!utgpu!attcan!telly!druid!darcy
From: darcy@druid.uucp (D'Arcy J.M. Cain)
Newsgroups: comp.lang.c
Subject: Re: malloc/free question
Message-ID: <1990May3.135327.28940@druid.uucp>
Date: 3 May 90 13:53:27 GMT
References: <2638831C.728C@telly.on.ca> <1990Apr28.020711.8639@druid.uucp> <6822@jarthur.Claremont.EDU>
Reply-To: darcy@druid.UUCP (D'Arcy J.M. Cain)
Organization: D'Arcy Cain Consulting, West Hill, Ontario
Lines: 35

In article <6822@jarthur.Claremont.EDU> dfoster@jarthur.Claremont.EDU (Derek R. Foster) writes:
>In article <1990Apr28.020711.8639@druid.uucp> darcy@druid.UUCP (D'Arcy J.M. Cain) writes:
>>Well I have never seen the source for a malloc and I don't know how it is
>>normally done but a moment's thought will suggest that the above can't work.
>>Consider the following:
>>    char *ptr = malloc(64);
>>    strcpy(ptr, "Stomp on the malloc structure");
>>    free(ptr);
>
>Wellllll.... not necessarily.
>Remember, malloc usually allocates a few more bytes than you ask it to.
>The extra info could be stored at the beginning of the structure

Here is the original suggestion I was responding to:

<I suggested that malloc probably returns a pointer to a structure that has
<a pointer to the "allocated" memory and also the number of bytes that were
<allocated, so, when the free function is called using the pointer to the
<structure, free uses the bytes allocate member of that structure to 
<"de-allocate" the memory.  

And all I tried to say was that that couldn't work.  Any implementation
*MUST* return a pointer to actual memory that the caller can write to.  If,
as the first poster suggested, malloc returned "a pointer to a structure
that has a pointer to the allocated memory ..." then the above strcpy would
be impossible.

So if everyone would please stop sending me mail explaining how malloc
works?

-- 
D'Arcy J.M. Cain (darcy@druid)     |   Government:
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