Path: utzoo!attcan!darkover!telly!eci386!jmm
From: jmm@eci386.uucp (John Macdonald)
Newsgroups: comp.lang.c
Subject: Re: #define DEBUG... (using printf for debugging)
Message-ID: <1990May8.133742.10584@eci386.uucp>
Date: 8 May 90 13:37:42 GMT
References: <11290@hoptoad.uucp> <40628@cornell.UUCP> <2294@awdprime.UUCP>
Reply-To: jmm@eci386.UUCP (John Macdonald)
Organization: Elegant Communications Inc., Toronto, Canada
Lines: 35

In article <2294@awdprime.UUCP> tif@awdprime.austin.ibm.com.UUCP (/32767) writes:
|Most people I know of do
|	#define DEBUG(xx)	printf xx
|and then
|	DEBUG(("the flag is %d\n", flag));
|The whole thing is completely removed with
|	#define DEBUG(xx)

The same sequence has been suggested numerous times in previous
messages.

The double parentheses in this solution are annoying, and error-prone,
and not really required.

Try the following instead:

    #ifdef DEBUG_PRINT_ON
    #   define DEBUG printf
    #else
    #   define DEBUG(ignore)
    #endif

To insert a DEBUG-conditional printf use:

    DEBUG( "format", args, ... );

(no double parens or other funny syntax required, it just looks like
a function call)

If you prefer, you can comment out one of the defines rather than
controlling it with an ifdef.
-- 
Algol 60 was an improvment on most           | John Macdonald
of its successors - C.A.R. Hoare             |   jmm@eci386