Path: utzoo!utgpu!news-server.csri.toronto.edu!mailrus!iuvax!silver!rschmidt
From: rschmidt@silver.ucs.indiana.edu (roy schmidt)
Newsgroups: comp.lang.c
Subject: Re: how do I do a 'readln' in C ??
Summary: KISS
Message-ID: <45851@iuvax.cs.indiana.edu>
Date: 26 May 90 03:36:32 GMT
References: <1382@sumax.UUCP> <1990May16.064747.22020@iesd.auc.dk> <196@taumet.COM>
Sender: root@iuvax.cs.indiana.edu
Organization: Indiana University, Bloomington IN.
Lines: 34

In article <196@taumet.COM> steve@taumet.UUCP (Stephen Clamage) writes:
>In article <1990May16.064747.22020@iesd.auc.dk> kjeld@iesd.auc.dk (Kjeld Flarup) writes:
>>In article <1382@sumax.UUCP> cadwell@sumax.UUCP (James A. Cadwell) writes:
>>>Simple question which I hope has a simple answer: how does one consume an
>>>in put line in C. Pascal wise it's 'readln'.
>>> 
>>>thank you, Jim
>>This is my simple solution. It reads until it encounters a eoln, EOF or fills
>>the buffer
>
>Well, a standard C function does precisely this, with no code to write.
>    char *fgets(char *s, int n, FILE *f);
>"s" is an array to fill, and at most n-1 characters
>will by copied from file "f", but not beyond a newline or EOF (the newline
>is in the buffer as a '\n' character).  The string in "s" is always
>terminated by a null character.  "fgets" returns null pointer on error,
>"s" otherwise.

Maybe so, but even simpler is:

     int c;

     while ((c = getchar()) != EOF && c != '\n')
          ;
     c = getchar();

And the input line is gone.  Oh, you meant you want to keep the input
line?  Arf Arf.
-----------------------------------------------------------       ^
Roy Schmidt                 |  #include <disclaimer.h>           | |
Indiana University          |  /* They are _my_ thoughts,        | |
Graduate School of Business |     and you can't have them,      <   >
Bloomington                 |     so there! */                    X
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