Path: utzoo!attcan!uunet!mcsun!hp4nl!ruuinf!accucx!aceverj
From: aceverj@accucx.cc.ruu.nl (Jaap Verhage)
Newsgroups: comp.sys.ibm.pc
Subject: Speed of coprocessor vs. speed of main processor
Message-ID: <459@accucx.cc.ruu.nl>
Date: 10 Jun 90 11:36:29 GMT
References: <3076@crash.cts.com>
Reply-To: aceverj@accucx.UUCP (Jaap Verhage)
Organization: Academic Computer Centre Utrecht, The Netherlands
Lines: 10

In article <3076@crash.cts.com> jca@pnet01.cts.com (John C. Archambeau) writes:
(among many other things):
>On a a 286, it's the clock crystal divided by 2 to get the clock speed of the
>CPU.  On the math coprocessor, it's the crystal divided by three or four.
I've often wondered about this: the speed of the math
coprocessor may be lower than that of the main processor?
E.g., if I've got a 12MHz 80286, I can use a 10MHz 80287 with
it, or something? Would a knowledgeable soul please email me
with an explanation/clarification? I'll summarize for the
newsgroup.