Path: utzoo!attcan!uunet!snorkelwacker!bloom-beacon!itstd.sri.COM!davy
From: davy@itstd.sri.COM
Newsgroups: comp.windows.x
Subject: how do you get correct window position?
Message-ID: <9006131913.AA02147@intrepid.itstd.sri.com>
Date: 13 Jun 90 19:13:14 GMT
Sender: root@athena.mit.edu (Wizard A. Root)
Organization: The Internet
Lines: 42


Given the following code fragment:

	Widget w, toplevel;

	toplevel = ...

	w = XtCreatePopupShell(name, wmShellWidgetClass, toplevel,
		args, nargs);

	/* create widgets inside the shell widget */

How do I get the *correct* (x,y) position of the window belonging to
the shell widget so I can create another one in exactly the same
place?  Currently, I am doing:

	WindowAttributes win_attributes;

	XGetWindowAttributes(display, XtWindow(w), &win_attributes);

	XTranslateCoordinates(display, XtWindow(w), root_window,
		win_attributes.x, win_attributes.y, &savex, &savey, &junk);

and then using savex and savey.  However, when I recreate the shell
widget in the next invocation of the program, using savex and savey in
the geometry argument, the window is a couple of pixels down and to
the right.  So every time I save the position and recreate, the window
moves a little bit.  Not good.

As near as I can figure, since twm is putting a border on the window
of the shell widget, I need to be taking that into account.  But I've
been running through the manuals for an hour and a half and can't find
any routine which will tell me how big the border twm is sticking on
there is!

Can anyone suggest how to do this?  (Note: I'm not particularly attached
to using XGetWindowAttributes, so if there's a better function, please
let me know.)

Thanks,
Dave Curry
davy@itstd.sri.com