Path: utzoo!attcan!uunet!mcsun!hp4nl!star.cs.vu.nl!maart
From: maart@cs.vu.nl (Maarten Litmaath)
Newsgroups: comp.unix.questions
Subject: Re: regexp..prepending a line globally (Vi)
Message-ID: <7047@star.cs.vu.nl>
Date: 2 Jul 90 15:12:50 GMT
References: <1772@island.uu.net>
Sender: news@cs.vu.nl
Reply-To: maart@cs.vu.nl (Maarten Litmaath)
Organization: VU Informatika, Amsterdam, The Netherlands
Lines: 42

In article <1772@island.uu.net>,
	daniel@island.uu.net (Daniel Smith - OPD Gang) writes:
)...
)/usr/spool/ftp/comp.sources.unix/volume22/nn6.4:
)part01.Z
)part02.Z
)part03.Z
)part04.Z
).
).
). etc...
)
)	So far so good.  Now what I wanted to do is take the first
)line (with the path) and prepend it to every line with a regexp.  [...]

Not so trivial, I think.  The following sh/sed solution works.
Try to figure it out!
--------------------cut here--------------------
SED='
	/spool/{
: dir
		s/:$/\//
		h
: file
		n
		/spool/b dir
		H
		g
		s/\n//
		p
		x
		s/\n.*//
		x
		b file
	}
	p
'

sed -n "$SED" ls-output-file
--
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