Path: utzoo!attcan!uunet!mcsun!hp4nl!phigate!ehviea!leo
From: leo@ehviea.ine.philips.nl (Leo de Wit)
Newsgroups: comp.lang.c
Subject: Re: setting tab stops
Message-ID: <834@ehviea.ine.philips.nl>
Date: 18 Jul 90 16:35:12 GMT
References: <1037@rossignol.Princeton.EDU>
Reply-To: leo@ehviea.UUCP (Leo de Wit)
Organization: Philips I&E Eindhoven
Lines: 20

In article <1037@rossignol.Princeton.EDU> tr@samadams.princeton.edu (Tom Reingold) writes:
|This question is not relevant to C, but I saw a nice algorithm, and I
|think I saw it in comp.lang.c.  Someone posted a very terse way of
|calculating how many spaces to move given an input of tabs.  I think it
|used the modulo operator and some bitwise operators.  It was far too
|terse and elegant for me to think of.  Can someone express what I am
|thinking of?  The assumption is that the terminal tabs at every eighth
|position.
|--

If I understand you correctly, you want to know how many spaces to
output given an input of tabs (let's call it ntabs) and a current
column position (let's call it ccpos), so that the resulting column
position would be the same?
The current position is ccpos % 8 columns past the last tabstop, so you
must move - (ccpos % 8) columns to get back to the previous tabstop,
then 8 columns forward for each tab. This results in 8 * ntabs - (ccpos
% 8) spaces, which also could be expressed as (ntabs << 3) - (ccpos & 7).

    Leo.