Path: utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!swrinde!zaphod.mps.ohio-state.edu!nisca.ircc.ohio-state.edu!hpuxa.ircc.ohio-state.edu!frank From: frank@hpuxa.ircc.ohio-state.edu (Frank G. Fiamingo) Newsgroups: comp.unix.questions Subject: Re: Ethernet question Message-ID: <2818@nisca.ircc.ohio-state.edu> Date: 16 Jul 90 18:57:43 GMT References: <1990Jul14.063620.4375@iwarp.intel.com> <23877@adm.BRL.MIL> Sender: news@nisca.ircc.ohio-state.edu Reply-To: frank@hpuxa.ircc.ohio-state.edu Organization: The Ohio State University (IRCC) Lines: 28 In article <1990Jul14.063620.4375@iwarp.intel.com>, merlyn@iwarp.intel.com (Randal Schwartz) writes: > In-Reply-To: terry@cssun.tamu.edu (Terry Escamilla) > > In article <23877@adm.BRL.MIL>, terry@cssun (Terry Escamilla) writes: > | Is it possible for a workstation on an Ethernet to dynamically > | determine the Internet (or even Ethernet) addresses of the > | hosts/workstations immediately to its left and right? > | I guess this would be like an "intelligent" ping or ARP. > > Ethernet is flat. (Well, OK, the cable is round. :-) Your broadcasts > are flooded to every reciever on the cable. There's no left or right > in electron space. > > Just another cybernetic hallucination, > -- While it's true that the broadcasts are flooded to all receivers on the cable, it's not truly "flat". It takes a definite time for the electron to traverse any length of the cable. Conceivably one could measure the time it takes for a signal to bounce back to the original machine and convert that to distance. Frank Frank Fiamingo frank@hpuxa.ircc.ohio-state.edu (614)292-4843