Path: utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!uunet!microsoft!steveha
From: steveha@microsoft.UUCP (Steve Hastings)
Newsgroups: comp.editors
Subject: Re: ex search & substitution question
Message-ID: <56403@microsoft.UUCP>
Date: 8 Aug 90 16:25:35 GMT
References: <3440001@hprnd.HP.COM> <26814@nigel.ee.udel.edu> <1990Aug07.174235.28911@hoss.unl.edu>
Reply-To: steveha@microsoft.UUCP (Steve Hastings)
Organization: Microsoft International Products Group
Lines: 21

In article <1990Aug07.174235.28911@hoss.unl.edu> sanjiv@hoss.unl.edu (Sanjiv K. Bhatia) writes:
>In article <26814@nigel.ee.udel.edu> new@ee.udel.edu (Darren New) writes:
>>Try 
>>:10,20g/^#[iut]55/s/55/71/
>>
>
>Here is my $0.02 worth.  I prefer to use the substitute command 's'.
>
>:10,20s/^#[iut]55/77/

This will replace everything with "77".  Try this:

:10,20s/^\(#[iut]\)55/\177/
         ^^      ^^   ^^

The \( \) quotes part of the match pattern, and the \1 evaluates to the
quoted pattern.  You can have up to 9 pairs of \( \), referred to as \1 to \9
in the replacement part.  But for this example, I think the g// is better.
-- 
Steve "I don't speak for Microsoft" Hastings    ===^=== :::::
uunet!microsoft!steveha  steveha@microsoft.uucp    ` \\==|