Path: utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!swrinde!zaphod.mps.ohio-state.edu!samsung!munnari.oz.au!goanna!minyos!monu6!edp367s
From: edp367s@monu6.cc.monash.edu.au (Rik Harris)
Newsgroups: comp.editors
Subject: Re: ex search & substitution question
Message-ID: <1990Aug9.003212.12140@monu6.cc.monash.edu.au>
Date: 9 Aug 90 00:32:12 GMT
References: <3440001@hprnd.HP.COM> <26814@nigel.ee.udel.edu> <1990Aug07.174235.28911@hoss.unl.edu>
Organization: Chisholm Institute of Technology, Melb., Australia
Lines: 35

sanjiv@hoss.unl.edu (Sanjiv K. Bhatia) writes:

>In article <26814@nigel.ee.udel.edu> new@ee.udel.edu (Darren New) writes:
>>In article <3440001@hprnd.HP.COM> brent@hprnd.HP.COM (Brent McInnis) writes:
>>>But to perform it on a *range* of lines (say, lines 10 thru 20), I
>>>*want* to say
>>>:10,20/^#[iut]55/s/55/71/
>>within the range that also match the pattern.       -- Darren

[stuff deleted]

>Here is my $0.02 worth.  I prefer to use the substitute command 's'.

>:10,20s/^#[iut]55/77/

no, this will delete the letter at the start, the letter must stay.

a more complicated solution is required:

:10,20s/\(^#[iut]\)55/\177/

this puts the letter at the start in a variable called \1, and replaces the
whole string with the letter followed by the 77.

I e-mailed the author of the original article, but it looks like there's some
others who might benefit from this.

rik.

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Rik Harris - Monash University, Caulfield Campus (was Chisholm Institute)
edp367s@monu6.cc.monash.edu.au     <-- what the computer says it is
edp367s@monu6.cc.monash.oz[.au]    <-- SEEMS to work more reliably
Build a system that even a fool can use, and only a fool will want to use it.
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