Path: utzoo!utgpu!news-server.csri.toronto.edu!rutgers!usc!samsung!uunet!dg!vis01!mpogue
From: mpogue@vis01.dg.com (Mike Pogue)
Newsgroups: comp.graphics
Subject: Re: Euler's rotation
Keywords: rotation, quaternion, Euler
Message-ID: <762@dg.dg.com>
Date: 13 Aug 90 17:24:58 GMT
References: <580@dg.dg.com> <9715@goofy.Apple.COM>
Sender: root@dg.dg.com
Reply-To: mpogue%dg.dg.com@vis01.dg.com
Organization: Data General, Westboro, MA.
Lines: 22


In article <9715@goofy.Apple.COM>, turk@Apple.COM (Ken "Turk" Turkowski)
writes:
|> In article <580@dg.dg.com> mpogue@dg.dg.com writes:
|> >
|> >   Does anybody have this formula handy?
|> 
|> If you really need the axis and angle, you might be able to do this
|> by computing the eigenvectors of the matrix.  I believe that Ned


   Thanks....I was actually able to derive the result, as a product of
three quaternions.  Once I realized that I could use quaternion 
arithmetic, the three rotations were pretty easy.  I'm sure that there
is a closed form that would be much simpler, but I haven't had time to
teach Mathematica about quaternions, so I could auto-simplify my
expressions.  I don't have enough time to sit down and do it by hand.

Mike Pogue
Data General Corp.

  Speaking for myself alone....