Xref: utzoo rec.video:14128 comp.misc:9850 Path: utzoo!utgpu!news-server.csri.toronto.edu!mailrus!uunet!tut.cis.ohio-state.edu!ucsd!rutgers!bellcore-2!bellcore!pyuxp!pyuxe!nvuxr!ccw From: ccw@nvuxr.UUCP (christopher wood) Newsgroups: rec.video,comp.misc Subject: Video and computer memory Message-ID: <1815@nvuxr.UUCP> Date: 17 Aug 90 22:32:04 GMT References: <29@meme.stanford.edu> <1990Jul31.204803.25358@eng.umd.edu> <11312@odin.corp.sgi.com> Reply-To: ccw@nvuxr.UUCP (22456-christopher wood) Followup-To: rec.video Organization: Bell Communications Research, NJ Lines: 20 I decided not to quote the earlier articles, anyway. The question is, how much computer memory do you need to hold video information? Lots of x pixels/line by y lines/frame by z frames per second by q bits/pixel formulas were suggested. Picking up a handy reference volume, I discover that "the networks" use "the telepohone network" to carry their video. They do this on a digital channel that carries 45 MegaBITS per second. I am not sure about the encoding, but I'm sure that it's clever, but relatively simple. Using this number, each minute of video would take up 337 MegaBYTES of storage. -- Chris Wood Bellcore ...!bellcore!nvuxr!ccw or ccw@nvuxr.cc.bellcore.com