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From: joonsong@monsoon.Berkeley.EDU (Suk-Hyun Song)
Newsgroups: comp.sys.ibm.pc.misc
Subject: Re: Re: DR-DOS ver 5.0 (now *very* long, biased opinion;-)
Message-ID: <1990Aug21.195452.23710@agate.berkeley.edu>
Date: 21 Aug 90 19:54:52 GMT
References: <9K1N7K1@drivax.UUCP> <35010004@hpfinote.HP.COM> <3944@bwdls58.UUCP>
Sender: usenet@agate.berkeley.edu (USENET Administrator;;;;ZU44)
Reply-To: joonsong@monsoon.Berkeley.EDU (Joon Song)
Organization: ucb
Lines: 17

In article <3944@bwdls58.UUCP> mlord@bwdls58.bnr.ca (Mark Lord) writes:
>In article <35010004@hpfinote.HP.COM> pnl@hpfinote.HP.COM (Peter Lim) writes:
>>... you'll never be able to get > 600 K free with MS-DOS
>>and one of QRAM, 386MAX etc. (unless you use hercules card). This is
>>because MS-DOS must reside in low memory.
>
>How strange.  On my MSDOS 3.3 system, I have about 612K free with QEMM.
>This is a VGA system, with 4DOS as the command interpreter.

I suppose this is all a matter of definition.

Does a 640K computer have 640000 bytes or 655360?
If you think 1K = 1024 bytes, then 600K = 614400 bytes.
       Or if 1K = 1000 bytes, then 600K = 600000 bytes.

Nobody is really wrong.  The question is, does DR-DOS 5.0 provide
620*1000 bytes or 620*1024 bytes?