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From: rsl@cbnewsm.att.com (randolph.little)
Newsgroups: comp.unix.questions
Subject: Re: Which script (was Re: comp.unix.questions)
Summary: revised shell script
Keywords: shell script, directory
Message-ID: <1990Sep10.185245.25531@cbnewsm.att.com>
Date: 10 Sep 90 18:52:45 GMT
References: <1990Sep7.152354.9439@ecn.purdue.edu> <563@DIALix.UUCP>
Organization: AT&T Bell Laboratories
Lines: 51

In article <563@DIALix.UUCP>, bernie@DIALix.oz.au (Bernd Felsche) writes:
> In article <1990Sep7.152354.9439@ecn.purdue.edu> patkar@helium.ecn.purdue.edu (The Silent Dodo) writes:
> >I have a question about shell scripts.  How can a shell script
> >(sh or csh) find out its own file name?
> 
> The solution is to parse the current PATH if the program name does
> not begin with a '/'. On a BSD machine, you can use the 'which'
> command (come Sys V have it also), or you can work it out by:
> 
> :
> # bourne shell script template
> #
> 
> prog=$0
> case $prog in
> 	/*)	echo $i
#                    ^^^   Should be $0
> 		break
> 		;;
# Add test for explicit current directory search:
	./*)	echo `pwd`/`basename $0`
		break
		;;
> 	*)
> 		OIFS="$IFS"
> 		IFS=":$IFS"
> 
> 		for i in $PATH
> 		do
> 			if [ -x $i/$prog ]
> 			then
> 				break
> 			fi
> 		done
> 		echo $i/$prog
> 		IFS="$OIFS"
> 		;;
> esac
> 
> Instead of the echo's, you can use a fullname= etc to find what you
> need.  To get the directory name is left as an exercise :-)
> 
> bernie
> 
> p.s.  Send no cash.  Just Bullion.

The first change corrects a typo, where $i should be $0; while the
second change adds another pattern to handle the case where the command
is invoked in the working directory by typing ./command (which bypasses $PATH).

Randolph S. Little <randolph.little@att.com>