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From: cameron@usage.csd.oz (Cameron Simpson,Uhmmm..???? Who knows)
Newsgroups: comp.std.c
Subject: Re: Why no logical XOR operator
Message-ID: <852@usage.csd.unsw.oz.au>
Date: 16 Sep 90 04:42:31 GMT
References: <1990Sep14.185916.2247@basho.uucp>
Sender: news@usage.csd.unsw.oz.au
Reply-To: cameron@spectrum.cs.unsw.oz.au (Cameron Simpson)
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Lines: 16

From article <1990Sep14.185916.2247@basho.uucp>, by john@basho.uucp (John Lacey):
|cameron@usage.csd.oz (Cameron Simpson,Uhmmm..???? Who knows) writes:
|>	- What's wrong with saying:
|>		!!x ^ !!y
|>	  which accomplishes exactly what you want.
| 
| What?  If x = y = 1, then !!x = !!y = 1, and 1 ^ 1 = 1, but x ^^ y = 0.

Run that by me again? `1 ^ 1 = 1' ? You sure learnt logic in a different
school from me. Of course, one can be even terser and say
	!x ^ !y
instead of
	!!x ^ !!y
but the effect is the same.
	- Cameron Simpson
	  cameron@spectrum.cs.unsw.oz.au