Path: utzoo!attcan!uunet!samsung!noose.ecn.purdue.edu!mentor.cc.purdue.edu!seaman.cc.purdue.edu!ags From: ags@seaman.cc.purdue.edu (Dave Seaman) Newsgroups: comp.sys.handhelds Subject: Re: Question - Indefinite Integration Message-ID: <14784@mentor.cc.purdue.edu> Date: 4 Oct 90 17:54:22 GMT References: <24605@uflorida.cis.ufl.EDU> <19080015@hpfinote.HP.COM> <1990Oct4.005626.33899@eagle.wesleyan.edu> Sender: news@mentor.cc.purdue.edu Reply-To: ags@seaman.cc.purdue.edu (Dave Seaman) Organization: Purdue University Lines: 23 In article <1990Oct4.005626.33899@eagle.wesleyan.edu> flinton@eagle.wesleyan.edu writes: >In section 4 of Chapter 9 (pp. 172-175) you find the author's approach >to plotting an indefinite integral over a given range. If you mean an "indefinite integral" in the sense that most people have been using the term in this newsgroup (i.e. an integral with no specified limits, yielding an answer that includes a constant of integration), then the plot is exceedingly simple. It is all black. In some quarters, the term "indefinite integral" means an integral of the form F(x) = (integral from a to x) f(t) dt where a is a constant. For some reason, I get the feeling that that is not what people have been asking for when they say they want to do indefinite integrals on the HP48. -- Dave Seaman ags@seaman.cc.purdue.edu