Path: utzoo!attcan!uunet!samsung!noose.ecn.purdue.edu!mentor.cc.purdue.edu!seaman.cc.purdue.edu!ags From: ags@seaman.cc.purdue.edu (Dave Seaman) Newsgroups: comp.sys.handhelds Subject: Re: Interestring Property of HP-* Calculators Keywords: 48SX,COS Message-ID: <15670@mentor.cc.purdue.edu> Date: 25 Oct 90 15:09:23 GMT References: <2821@uc.msc.umn.edu> <15610@mentor.cc.purdue.edu> <2830@uc.msc.umn.edu> Sender: news@mentor.cc.purdue.edu Reply-To: ags@seaman.cc.purdue.edu (Dave Seaman) Organization: Purdue University Lines: 24 In article <2830@uc.msc.umn.edu> fin@norge.unet.umn.edu (Craig A. Finseth) writes: >I think that you missed the point. I know perfectly well about how >fixed point arithmetic works and about fixed points of functions. >That was the preface. The obvservation was that COS(x) had a fixed >point but ACOS(x) did not. Actually, the observation was (quoting from 2821@uc.msc.umn.edu): >Obviously, the ACOS algorithm has a different fixed point if, indeed, >it has one at all. The Solver reports a sign reversal for: > > 'ACOS(X)=X' > >at, oddly enough, .9998447741531. The fact that you thought there might be a different fixed point, plus the fact that you seemed to be surprised at the apparent coincidence that the sign reversal occurred at precisely the right value, led me to believe that you might not understand the mathematical properties of your example. That is what I tried to explain. -- Dave Seaman ags@seaman.cc.purdue.edu