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From: catfood@NCoast.ORG (Mark W. Schumann)
Newsgroups: comp.lang.c
Subject: Re: # to the nth power
Message-ID: <1990Nov1.232830.17131@NCoast.ORG>
Date: 1 Nov 90 23:28:30 GMT
References: <90305.005050CJH101@psuvm.psu.edu-> <15984@mentor.cc.purdue.edu-> <9750@helios.TAMU.EDU>
Organization: North Coast Public Access *NIX, Cleveland, OH
Lines: 46

In article <9750@helios.TAMU.EDU> randy@cs.tamu.edu (Randy Hutson) writes:
>In article <15984@mentor.cc.purdue.edu-> edgincd2@mentor.cc.purdue.edu (Chris Edgington *Computer Science Major*) writes:
>->In article <90305.005050CJH101@psuvm.psu.edu->, CJH101@psuvm.psu.edu (Carl J. Hixon) writes:
>->-> I appologize for bothering you computer wizards with such an elementary
>->-> question but, I'm floundering.  Why am I unable to find an opperator which
>->-> raises a number to a power. (The fortran equivalent of x**n)  Is there such
>->
>->I don't know if this is what you are looking for, but this is a neat little
>->trick to take a number to a power.
>->
>->     Answer = exp(ln(Root)*Exponent);
>->
>->Chris Edgington
>
>I use an even neater trick!
>	
>	Answer = pow(Root, Exponent);
Randy's answer presumes you have the 'pow' function in your library.
It *is* part of the ANSI standard, so if your compiler is ANSI, you're
groovin'.

If you are interested in an
integer version of the same function, try this:

int powi (int root, int exponent)

{

int i;
int result = 1;

  for (i = exponent; i > 1; i--) result *= root;
  return result;

  }

Now you've gotta be careful about overflow here or use long ints.
If you needed an integer version I hope this helps.


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