Path: utzoo!utgpu!watserv1!watmath!att!att!emory!wuarchive!cs.utexas.edu!sun-barr!apple!olivea!orc!inews!cmdnfs!bhoughto From: bhoughto@cmdnfs.intel.com (Blair P. Houghton) Newsgroups: comp.std.c Subject: Re: strings no longer writable? Message-ID: <681@inews.intel.com> Date: 29 Oct 90 23:26:43 GMT References: <1990Oct29.174410.28498@batcomputer.tn.cornell.edu> Sender: news@inews.intel.com Organization: Intel Corp, Chandler, AZ Lines: 38 In article <1990Oct29.174410.28498@batcomputer.tn.cornell.edu> lijewski@theory.tn.cornell.edu (Mike Lijewski) writes: > >My understanding is that strings are no longer writable. That is to say, >the assignment to s[5] in the below program shouldn't be allowed. > >main() { char *s = "testing"; s[5] = 'z'; } Correct. However, if you had done main() { char s[] = "testing"; s[5] = 'z'; } s would itself be an array and be writable; it is considered identical to having done main() { char s[] = {'t','e','s','t','i','n','g','\0'}; s[5] = 'z'; } (cf. ANSI X3.159-1989, sec. 3.5.7, p. 75, ll. 24-30) >Is a conforming implementation required to issue a warning, an error, or >what? "...the declaration char *p = "abc"; defines p with type `pointer to char' that is initialized to point to an object with type `array of char' with length 4 whose elements are initialized with a character string literal. If an attempt is made to use p to modify the contents of the array, the behavior is undefined." (ibid., ll. 30-34) Therefore, it's entirely up to your implementor. --Blair "Harder to find than to understand..."