Xref: utzoo sci.electronics:15329 rec.ham-radio:26426 Path: utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!swrinde!zaphod.mps.ohio-state.edu!usc!chaph.usc.edu!aludra.usc.edu!kjh From: kjh@aludra.usc.edu (Kenneth J. Hendrickson) Newsgroups: sci.electronics,rec.ham-radio Subject: Re: A question about a PLL synth loop filter Message-ID: <12890@chaph.usc.edu> Date: 1 Nov 90 22:05:53 GMT References: <1990Oct31.210242.20619@aplcen.apl.jhu.edu> Sender: news@chaph.usc.edu Followup-To: sci.electronics Organization: EE-Systems, USC, Los Angeles Lines: 33 Nntp-Posting-Host: aludra.usc.edu In article <1990Oct31.210242.20619@aplcen.apl.jhu.edu> @aplvax.jhuapl.edu:mjj@stda.jhuapl.edu (Marshall Jose) writes: %I have been trying to understand a passive loop filter I have twice seen used %in ham radio construction articles. It looks like this: % % % O---VVVVV----+-------+------O % R1 | | % | > % | > R2 % | > % --- | % --- C1 | % | | % | --- % | --- C2 % | | % O------------+-------+------O % % % C(as + 1) % H(s) = --------------------- % 3 2 % s + ps + qs + r % Your first clue, is that since you have two energy storage devices, that you should have two poles. When I solve this, I get: c1r1 * s + 1 H(s) = --------------------------------------------- c1c2r1r2 * s^2 + (c2r2 + c1r1 + c2r1) * s + 1 Ken Hendrickson N8DGN/6 kjh@usc.edu ...!uunet!usc!pollux!kjh