Path: utzoo!attcan!uunet!fernwood!lia!jgro
From: jgro@lia (Jeremy Grodberg)
Newsgroups: comp.lang.c++
Subject: Re: operator&
Message-ID: <1990Nov6.002221.3635@lia>
Date: 6 Nov 90 00:22:21 GMT
References: <fuchs.657417082@t5000>
Reply-To: jgro@lia.com (Jeremy Grodberg)
Lines: 16

In article <fuchs.657417082@t5000> fuchs@it.uka.de (Harald Fuchs) writes:
<I tried to define a counted pointer class "Xptr" to another class "X"
<and ran into a problem with the address-of "operator&". I redefined
<this operator to return a counted rather than a normal pointer, but for
<Xptr::operator-> () I need the real address of my X object (i.e. an X*
<rather than an Xptr). Is there a way to access the "normal" address-of
<operator even if it is redefined for a user-defined type?
<    //X* operator-> () const { return &p->obj; }  // This won't work

try 
  X* operator-> () const { return ::operator&(p->obj); }

::operator&()  explicitly calls the global non-overloaded & operator.
-- 
Jeremy Grodberg      "I don't feel witty today.  Don't bug me."
jgro@lia.com