Newsgroups: comp.lang.c
Path: utzoo!telly!druid!darcy
From: darcy@druid.uucp (D'Arcy J.M. Cain)
Subject: Re: sizeof() confusion
Organization: D'Arcy Cain Consulting, West Hill, Ontario
Date: Sat, 10 Nov 90 12:32:04 GMT
Message-ID: <1990Nov10.123204.8968@druid.uucp>
References: <9156@latcs1.oz.au> <27432@mimsy.umd.edu> <2665@cirrusl.UUCP>

In article <2665@cirrusl.UUCP> Rahul Dhesi writes:
> [...]
>     main() {
>        char c;
>        c = 'c';     /* char variable holds char value */
>
>        printf("sizeof c       = %d\n", sizeof c);
>        printf("sizeof 'c'     = %d\n", sizeof 'c');
>        printf("sizeof (char)  = %d\n", sizeof (char));
>     }
>
>Non-C wizards should try to guess what the program will print before
>they run the program.

OK, I'll byte.  What's the suprise?  I get 1, 4 and 1 on my 386 system
which is exactly what I expected.  Were you suprised that "'c'" was 4?
You shouldn't be.  That expression evaluates to an int, not a char.

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D'Arcy J.M. Cain (darcy@druid)     |
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