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From: merlyn@iwarp.intel.com (Randal Schwartz)
Newsgroups: comp.lang.perl
Subject: Re: Take the mod of a variable?
Message-ID: <1990Dec4.215840.10542@iwarp.intel.com>
Date: 4 Dec 90 21:58:40 GMT
References: <1990Dec03.160045.13310@cs.widener.edu>
Sender: news@iwarp.intel.com
Reply-To: merlyn@iwarp.intel.com (Randal Schwartz)
Organization: Stonehenge; netaccess via Intel, Beaverton, Oregon, USA
Lines: 21
In-Reply-To: brendan@cs.widener.edu (Brendan Kehoe)

In article <1990Dec03.160045.13310@cs.widener.edu>, brendan@cs (Brendan Kehoe) writes:
|  Is there any way to do something like $blah % 2  ($blah mod 2) ? I couldn't
| find anything in TFM.

Yeah, try $blah % 2. :-)

$ perl -e '$blah = 15; print $blah % 2;'
1

It isn't really in the manpage.  Basically, Perl expressions are
defined in terms of C expressions, and since % is not in the category
of "what C has that Perl doesn't"... Perl has it.

It's clearer in The Book (I know... that doesn't help just yet).

print "Just another Perl [book] hacker,"
-- 
/=Randal L. Schwartz, Stonehenge Consulting Services (503)777-0095 ==========\
| on contract to Intel's iWarp project, Beaverton, Oregon, USA, Sol III      |
| merlyn@iwarp.intel.com ...!any-MX-mailer-like-uunet!iwarp.intel.com!merlyn |
\=Cute Quote: "Intel: putting the 'backward' in 'backward compatible'..."====/


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