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From: ballou@databs.enet.dec.com
Newsgroups: comp.lang.lisp
Subject: Re: How to do set! on lists?
Message-ID: <1990Dec13.093956@databs.enet.dec.com>
Date: 13 Dec 90 14:48:24 GMT
References: <1990Dec12.173833.8352@Think.COM> <hobbit.660999284@shum>
Sender: newsdaemon@shlump.nac.dec.com
Reply-To: ballou@databs.enet.dec.com ()
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Organization: DEC, OODB
Lines: 23

In article <1990Dec12.173833.8352@Think.COM>, barmar@think.com (Barry Margolin)
writes:
|> In article <hobbit.660999284@shum> hobbit@huji.ac.il (yoav gonen) writes:
|> >I've already tried to do set! on lists and it did'n't worked out.
|> >I assume that I must use set-car! or set-cdr! in order to change a list,
|> >but if,for example i want to change a given list to a null one ( == '() )
|> >how can I do that???
|> 
|> [...nice explanation of basic lisp data structures...]
|>  
|> I hope this explanation helps, but I'm somewhat doubtful (no offense
|> intended).  The original question suggests a major lack of understanding of
|> Lisp data structures, and the above may confuse more than it helps.  I urge
|> you to seek out a local Lisp/Scheme programmer, or a good Lisp text
|> (unfortunately, few of the texts use Scheme, so you'll have to deal with
|> syntactic differences), and get enlightened.

Well done.  This is the only news group I know in which a novice would
be treated so gently.

My response might have been something like 'buy a clue, buddy'!

Must be working with C/C++ weenies too much...