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From: hodas@saul.cis.upenn.edu (Josh Hodas)
Newsgroups: comp.sys.mac.programmer
Subject: Re: Pascal deficiency?
Message-ID: <34996@netnews.upenn.edu>
Date: 18 Dec 90 15:12:18 GMT
References: <13650001@hpspdra.HP.COM> <1990Dec18.042748.6765@d.cs.okstate.edu>
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Reply-To: hodas@saul.cis.upenn.edu (Josh Hodas)
Organization: University of Pennsylvania
Lines: 68

In article <1990Dec18.042748.6765@d.cs.okstate.edu> minich@d.cs.okstate.edu (Robert Minich) writes:
>by stevewi@hpspdra.HP.COM (Steve Witten):
>| You can use the 'succ' and 'pred' operators/functions in Pascal to
>| accomplish the same function as '++' and '--'.  So:
>| 
>| 	integer i,j,k;
>| 
>| 	   ...
>| 
>| 	j := succ(i);  { same as 'j=i++' }
>| 	k := pred(i);  { same as 'k=i--' }
>| 
>| 	   ...
>| 
>| However, you have to remember that '++/--' are positional as well.
>| You cannot recreate this behavior.  You also cannot recreate the
>| behavior of 'x++' without an assignment in Pascal.
>
>  Do you not use C very often or are you VERY tired? The above Pascal
>statements are equivalent to
>
>	j := i + 1;
>	k := i - 1;
>
>whereas the C translates to Pascal as
>
>j = i++;         | j := j + i;
>                 | i := i + 1;
>k = i--;         | k := i - 1;
>                 | i := i - 1;
>


Robert,



  Do you not use C very often or are you VERY tired? 


Sorry, I couldn't resist.



j = i++		=>	j := i;
			i := i + 1;


K = i--		=>	K := i;
			i := i - 1;


and, for completeness:


j = ++i		=>	i := i + 1;
			j := i;
			

K = i--		=>	i := i - 1;
			k := i;


Josh
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