Path: utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!usc!ucsd!nosc!halibut.nosc.mil!koziarz From: koziarz@halibut.nosc.mil (Walter A. Koziarz) Newsgroups: sci.electronics Subject: Re: 116% Efficiency!!?? Message-ID: <3297@nosc.NOSC.MIL> Date: 26 Dec 90 18:47:46 GMT References: <2533@mentor.cc.purdue.edu> <17660134@hpfcdj.HP.COM> Sender: nobody@nosc.NOSC.MIL Organization: Naval Ocean Systems Center, San Diego Lines: 24 In article <17660134@hpfcdj.HP.COM> myers@hpfcdj.HP.COM (Bob Myers) writes: >someone (must be named 'Tom') wrote: >>Don't forget, you can have machines that you supply with, say, 1kW of >>electricity and which put >1kW of heat into your room. The _useful_ >>efficiency is thus >100%. > >OK, Tom, taking as implied that the 1kW of electricity is the only source >of power for the machine in question, exactly how is this done? > Not difficult, really, note the '_useful_' qualifier (I generally use _effective_ in the same context). Here's an example (with which I am *very* familiar :-): Ground-coupled heat-pump -- mine has a coefficient of performance (COP) of 3.20; this means that 3.2 watts of heat energy is delivered to my house for every watt of electric power supplied. Hence: 320% EFFECTIVE Efficiency. You will quickly note that I weasel-worded my reply, you don't get 'something for nothing'; the heatpump extracts heat from the ground via a normal refrigeration cycle and the electric power is *NOT* the only energy input. But as far as the dollars are concerned, it's 320% efficient. Walt K.