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From: wrf@mab.ecse.rpi.edu (Wm Randolph Franklin)
Newsgroups: sci.electronics
Subject: Re: 12V car --> 3V cd player
Keywords: CD, cd, cd player, car, power supply
Message-ID: <%BS^BG*@rpi.edu>
Date: 31 Dec 90 21:46:44 GMT
References: <1990Dec29.070556.7022@qiclab.uucp> <1990Dec31.081024.16910@yenta.alb.nm.us> <2374@casbah.acns.nwu.edu>
Organization: Rensselaer Polytechnic Institute, Troy NY
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In article <2374@casbah.acns.nwu.edu> squishy@casbah.acns.nwu.edu (Shishin Yamada) writes:
>
>+12V   Fuse    L1              1 _________ 2        D1   D2   D3
>O-------O~O---UUUUU---+------+---|       |-----+---->|--->|--->|----O  +3V
>                     +|      |   | 7805  |     | 
>                     ===    ===  |_______|    === C3
>Ground                | C1   | C2    |3        |
>O---------------------+------+-------+---------+--------------------O Ground
>
>	Where, L1 is say 1 uH, C1 is say 2200uF, C2 is 0.33uF, C3 is 0.1uF,
>D1 D2 and D3 are silicon rectifying diodes (like 1N4001). All components
>should be rated at least to 16 volts.

What does C2 do since it's so much smaller than C1?  My guess it that it
also has a smaller  inductance and  so traps hi  freqs better.   Is this
right?  Thanks.

-- 
						   Wm. Randolph Franklin
Internet: wrf@ecse.rpi.edu (or @cs.rpi.edu)    Bitnet: Wrfrankl@Rpitsmts
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Paper: ECSE Dept., 6026 JEC, Rensselaer Polytechnic Inst, Troy NY, 12180