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From: brnstnd@kramden.acf.nyu.edu (Dan Bernstein)
Newsgroups: comp.lang.c
Subject: Re: Need help with union trick
Message-ID: <27454:Jan302:07:4791@kramden.acf.nyu.edu>
Date: 3 Jan 91 02:07:47 GMT
References: <1991Jan3.005700.20623@lavaca.uh.edu>
Organization: IR
Lines: 47

In article <1991Jan3.005700.20623@lavaca.uh.edu> jet@karazm.math.uh.edu ("J. Eric Townsend") writes:
> I don't think this is possible in C (K&R or ANSI), but maybe someone
> can enlighten me as to the hows and whys of why it is/isnt' possible.
> I have a body of code with the following structure:
> typedef struct pointstruct {
>   double x,y,z;
>   } Point;
> I would like to be able to reference the elements as an array without
> having to rewrite the existing code. (We've got code to be pasted in that
> relies on being able to grab the x, y and z as array indicies. Grr. :-)

Well, the structure doesn't guarantee array alignment, so your basic
declaration has to be an array. Hence:

  typedef struct pointstruct
   {
    double a[3];
   }
  Point;
  #define x a[0]
  #define y a[1]
  #define z a[2]

This puts x, y, and z into the main namespace, and it may not be fully
efficient on some machines. If I were desperate I might try

  typedef struct pointstruct
   {
    double x; double y; double z;
   }
  Point;

  typedef union pointunion
   {
    struct pointstruct p;
    double a[3];
   }
  PU;

I seem to remember from previous discussions that (PU *) &p may not be
aligned correctly, where p has type Point. But if ((PU *) &p).a[0] has
the same address as p.x, ...a[1] as p.y, and ...a[2] as p.z, then you're
going to be safe in practice. If you think your CPU is going to blow up
when you try to compare &(((PU *) &p).a[0]) with &(p.x), don't use this
method.

---Dan