Path: utzoo!censor!geac!torsqnt!news-server.csri.toronto.edu!clyde.concordia.ca!thunder.mcrcim.mcgill.edu!snorkelwacker.mit.edu!think.com!samsung!dali.cs.montana.edu!milton!yoda.eecs.wsu.edu!pcooper
From: pcooper@eecs.wsu.edu (Phil Cooper - CS495)
Newsgroups: comp.sys.amiga.tech
Subject: Re: Help --> How to prevent the visit from the dreaded guru
Message-ID: <1991Jan06.231409.22606@eecs.wsu.edu>
Date: 6 Jan 91 23:14:09 GMT
References: <611@caslon.cs.arizona.edu> <1991Jan4.203339.8800@maytag.waterloo.edu> <V2H++Q_@irie.ais.org> <7463@sugar.hackercorp.com>
Reply-To: pcooper@yoda.UUCP (Phil Cooper - CS495)
Organization: Washington State University, Pullman
Lines: 27

In article <7463@sugar.hackercorp.com> peter@sugar.hackercorp.com (Peter da Silva) writes:
>In article <V2H++Q_@irie.ais.org> jph@ais.org (Joseph Hillenburg) writes:
>> Does anyone know how to FORCE a guru through C?
>
>	char *p;
>
>	for(p = 0; p != (char *)-1; p++)
>		*p = 0;
>
>This will certainly clobber the machine. Play with variations until you get
>the results you want. (sigh)
>-- 
>Peter da Silva.   `-_-'
><peter@sugar.hackercorp.com>.

OR, how 'bout a nice little divide by zero exception?

    int result,
        divisor = 0 ;

    result = 10/divisor ;

That should really throw it for a loop.

PC