Xref: utzoo sci.energy:3784 sci.electronics:16840 sci.physics:16313 Path: utzoo!utgpu!news-server.csri.toronto.edu!cs.utexas.edu!swrinde!zaphod.mps.ohio-state.edu!samsung!umich!sharkey!fmsrl7!teemc!fmeed1!cage From: cage@fmeed1.UUCP (Russ Cage) Newsgroups: sci.energy,sci.electronics,sci.physics Subject: Re: solar cells Summary: Tracker power drains are very small. Message-ID: <9284@fmeed1.UUCP> Date: 7 Jan 91 20:05:02 GMT References: <1990Dec17.190857.16559@engin.umich.edu> <37448@cup.portal.com> <1755@cluster.cs.su.oz.au> <5173@optilink.UUCP> Reply-To: russ@m-net.ann-arbor.mi.us (Russ Cage) Followup-To: sci.energy Organization: Ford Motor Co., Electronics Div., Dearborn, MI Lines: 24 In article <5173@optilink.UUCP> cramer@optilink.UUCP (Clayton Cramer) writes: >It used to mentioned as a problem on tours of Solar One. [....] >Also, they have lots of electric motors moving those mirrors >to track the Sun. How much electricity? I was told while I >was there in the early 1980s that they FINALLY were producing >more electricity than they were using. Even working against wind loads, the amount of power needed to track the sun is minuscule. 1/10 HP is overkill for all but the biggest arrays. Rapid tracking to stow mirrors in sandstorms would take more power, of course, but that is a transient and infrequent requirement. If the array catches 700 W/m^w and the system turns 20% of that into electricity, each square meter produces 140 watts, or about twice what the tracking motor needs. If each part of the array has 100 m^2 of area, then tracking takes about .005 of the energy output; not negligible, but far from a killer. -- Russ Cage Ford Powertrain Engineering Development Department Work: itivax.iti.org!cfctech!fmeed1!cage (CHATTY MAIL NOT ANSWERED HERE) Home: russ@m-net.ann-arbor.mi.us (All non-business mail) Member: HASA, "S" division.