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From: feuling@astroatc.UUCP (Lindsay Feuling)
Newsgroups: comp.lang.c,comp.sys.ibm.pc.misc,comp.os.msdos.programmer
Subject: QuickC stuff
Keywords: FPi87 flag
Message-ID: <3651@astroatc.UUCP>
Date: 18 Jan 91 17:31:43 GMT
Distribution: na
Organization: Astronautics Technology Cntr, Madison, WI
Lines: 25


On compiling my code with Microsoft Quick C 2.?, I put in the /FPi87
flag in the make file.  I'm not sure whether QuickC actually recognizes
this flag.  Also, in looking at the assembly code generated, I noticed that
it does not generate 8087 instructions.  What it actually does is generate
code to call some math emulator functions via interrupts, but I want to
run this code within an Interrupt Service Routine without goofing around
with calling other interrupt functions.
In looking at the code with CV, I found something of the following:
	int	37	;fild	dword ptr [FFfac (2009)]
	int	3d	;fwait
	les	bx,dword ptr [p_temp]
	int	3c	;fstp	dword ptr es:[bx]
	int	3d	;fwait

If it amounts to actually going into the assembly code and changing 
the assembly code so that the 8087 is used, then I will.  But not if
there's something that I have missed.  
Could anyone give me a clue as to what, if any, compiler flag will actually
put in 8087 in-line code (for real!) using QuickC?

Thanks
L. Feuling
Astronautics Tech. Ctr.
madison, wi