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From: prc@erbe.se (Robert Claeson)
Newsgroups: comp.unix.questions
Subject: Re: getting a field from a line in awk/sed/?
Message-ID: <1991Jan15.134416.27225@erbe.se>
Date: 15 Jan 91 13:44:16 GMT
References: <1991Jan9.162817.17038@porthos.cc.bellcore.com> <1991Jan10.012211.22100@ux1.cso.uiuc.edu>
Sender: prc@erbe.se (Robert Claeson)
Reply-To: prc@erbe.se (Robert Claeson)
Organization: ERBE DATA AB, Jakobsberg, Sweden
Lines: 20


In article <1991Jan10.012211.22100@ux1.cso.uiuc.edu>, gordon@osiris.cso.uiuc.edu (John Gordon) writes:

|> 	Well, this may not be perfect since I don't have an AWK reference
|> right here, but I think this will work:
|> 
|> 	(program that produces output) | awk '{print $2}'

|> 	If that does not work, try this:
|> 
|> 	awk -f <file that contains input> '{print $2}'

The former should work. The latter doesn't work. The -f flag to awk names a
file containing awk code to execute. But using "cut" is even easier (and
requires less typing) than using "awk".
-- 
Robert Claeson                  |Reasonable mailers: rclaeson@erbe.se
ERBE DATA AB                    |      Dumb mailers: rclaeson%erbe.se@sunet.se
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